What is x/((x^2+y^2))= 1/2 ?

The solution to x/((x^2+y^2))= 1/2 is Ellipse with (h,k)=(1,0),a=1,b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x/((x^2+y^2))= 1/2

\frac{x}{( x ^{2} + y ^{2} )} = \frac{1}{2}

(h, k) = (1, 0), a = 1, b = 1

Solution steps

\frac{x}{x ^{2} + y ^{2}} = \frac{1}{2}

Rewrite

\frac{x}{x ^{2} + y ^{2}} = \frac{1}{2}

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 0), a = 1, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 0), b = 1, a = 1

\frac{x ^{2}}{y ^{2} - 4} = - 4

1 x^{2} + 4 y^{2} + 9 x + 10 y - 14 = 0

x^{2} = 4 - 2 y^{2}

5 x^{2} + y^{2} + 4 x - 16 = 0

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 1 ) ^{2}}{4} = 1

What is x/((x^2+y^2))= 1/2 ?
The solution to x/((x^2+y^2))= 1/2 is Ellipse with (h,k)=(1,0),a=1,b=1