What is (x^2)/(100)+(y^2)/(49)=1 ?

The solution to (x^2)/(100)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=10,b=7

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(x^2)/(100)+(y^2)/(49)=1

\frac{x ^{2}}{100} + \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 10, b = 7

Solution steps

\frac{x ^{2}}{100} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{100} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 7

- x^{2} - 4 = y^{2}

x^{2} + 10 y^{2} - 6 x + 20 y + 18 = 0

\frac{( x - 1 ) ^{2}}{7 ^{2}} + \frac{( y - 1 ) ^{2}}{3 ^{2}} = 1

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{25} = 1

4 x^{2} + y^{2} - 8 x + 4 y - 4 = 0

What is (x^2)/(100)+(y^2)/(49)=1 ?
The solution to (x^2)/(100)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=10,b=7