What is ((x+1)^2}{25}+\frac{(y+2)^2)/9 =1 ?

The solution to ((x+1)^2}{25}+\frac{(y+2)^2)/9 =1 is Ellipse with (h,k)=(-1,-2),a=5,b=3

Popular >

((x+1)^2}{25}+\frac{(y+2)^2)/9 =1

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

(h, k) = (- 1, - 2), a = 5, b = 3

Solution steps

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 2), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 2), a = 5, b = 3

4 x^{2} + 9 y^{2} - 16 x - 54 y + 61 = 0

9 x^{2} + 25 y^{2} - 100 y - 125 = 0

x^{2} + 4 y^{2} + 10 x + 10 y - 8 = 0

16 x^{2} + 25 y^{2} - 96 x + 50 y - 231 = 0

(\frac{x ^{2}}{15}) + (\frac{y ^{2}}{16}) = 1

What is ((x+1)^2}{25}+\frac{(y+2)^2)/9 =1 ?
The solution to ((x+1)^2}{25}+\frac{(y+2)^2)/9 =1 is Ellipse with (h,k)=(-1,-2),a=5,b=3