What is ((x-2)^2)/(225)+((y-8)^2)/(81)=1 ?

The solution to ((x-2)^2)/(225)+((y-8)^2)/(81)=1 is Ellipse with (h,k)=(2,8),a=15,b=9

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((x-2)^2)/(225)+((y-8)^2)/(81)=1

\frac{( x - 2 ) ^{2}}{225} + \frac{( y - 8 ) ^{2}}{81} = 1

(h, k) = (2, 8), a = 15, b = 9

Solution steps

\frac{( x - 2 ) ^{2}}{225} + \frac{( y - 8 ) ^{2}}{81} = 1

Rewrite

\frac{( x - 2 ) ^{2}}{225} + \frac{( y - 8 ) ^{2}}{81} = 1

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{1 5 ^{2}} + \frac{( y - 8 ) ^{2}}{9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, 8), a = 15, b = 9

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, 8), a = 15, b = 9

1 x^{2} + 3 y^{2} + 10 x + 9 y - 10 = 0

2 x^{2} + 3 y^{2} + 8 x + 8 y - 10 = 0

\frac{2 - x ^{2} - y ^{2}}{x ^{2} + y ^{2} - 9} > 0

f (x) = x^{2} + 3 f (x) (f (x))

x^{2} + 4 y^{2} - 6 x - 8 y + 9 = 0

What is ((x-2)^2)/(225)+((y-8)^2)/(81)=1 ?
The solution to ((x-2)^2)/(225)+((y-8)^2)/(81)=1 is Ellipse with (h,k)=(2,8),a=15,b=9