What is 2= y/((y^2+x^2)) ?

The solution to 2= y/((y^2+x^2)) is Ellipse with (h,k)=(0, 1/4),a= 1/4 ,b= 1/4

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2= y/((y^2+x^2))

2 = \frac{y}{( y ^{2} + x ^{2} )}

(h, k) = (0, \frac{1}{4}), a = \frac{1}{4}, b = \frac{1}{4}

Solution steps

2 = \frac{y}{y ^{2} + x ^{2}}

Rewrite

2 - \frac{y}{y ^{2} + x ^{2}} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{4} ) ^{2}} + \frac{( y - \frac{1}{4} ) ^{2}}{( \frac{1}{4} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, \frac{1}{4}), a = \frac{1}{4}, b = \frac{1}{4}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, \frac{1}{4}), b = \frac{1}{4}, a = \frac{1}{4}

100 x^{2} + 64 y^{2} < 1600

9 x^{2} + 4 y^{2} + 90 x + 8 y + 193 = 0

25 x^{2} + 9 y^{2} + 50 x - 108 y + 124 = 0

2 x^{2} + y^{2} - 2 x + 16 y + 1 = 0

x^{2} + y^{2} + 2 y \leq 0

What is 2= y/((y^2+x^2)) ?
The solution to 2= y/((y^2+x^2)) is Ellipse with (h,k)=(0, 1/4),a= 1/4 ,b= 1/4