What is ((x+1)^2)/(25)+((y+2)^2)/(49)=1 ?

The solution to ((x+1)^2)/(25)+((y+2)^2)/(49)=1 is Ellipse with (h,k)=(-1,-2),a=5,b=7

Popular >

((x+1)^2)/(25)+((y+2)^2)/(49)=1

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

(h, k) = (- 1, - 2), a = 5, b = 7

Solution steps

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{5 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, - 2), a = 5, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 1, - 2), b = 7, a = 5

9 x^{2} + 4 y^{2} + 18 x - 8 y - 23 = 0

3 x^{2} + 4 y^{2} = 48

9 (x - 3)^{2} + 4 (y - 4)^{2} = 36

\frac{( x - 7 ) ^{2}}{3} + \frac{( y + 11 ) ^{2}}{5} = 1

5 y (y + 4 x) + 4 x^{2} = - 20 (1 - x) y + 5

What is ((x+1)^2)/(25)+((y+2)^2)/(49)=1 ?
The solution to ((x+1)^2)/(25)+((y+2)^2)/(49)=1 is Ellipse with (h,k)=(-1,-2),a=5,b=7