What is (x^2)/4+(y^2)/4+(x^2)/9 =1 ?

The solution to (x^2)/4+(y^2)/4+(x^2)/9 =1 is Ellipse with (h,k)=(0,0),a= 6/(sqrt(13)),b=2

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(x^2)/4+(y^2)/4+(x^2)/9 =1

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} + \frac{x ^{2}}{9} = 1

(h, k) = (0, 0), a = \frac{6}{13}, b = 2

Solution steps

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} + \frac{x ^{2}}{9} = 1

Rewrite

\frac{x ^{2}}{4} + \frac{y ^{2}}{4} + \frac{x ^{2}}{9} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{6}{13} ) ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{6}{13}, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = \frac{6}{13}

x^{2} + 4 y^{2} = 20

8 x^{2} + z^{2} = 36

\frac{( x - 1.23 ) ^{2}}{1.4 1 ^{2}} + \frac{y ^{2}}{1.00 7 ^{2}} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{5} = 1

9 x^{(2)} - 54 x + y^{(2)} - 2 y = - 81

What is (x^2)/4+(y^2)/4+(x^2)/9 =1 ?
The solution to (x^2)/4+(y^2)/4+(x^2)/9 =1 is Ellipse with (h,k)=(0,0),a= 6/(sqrt(13)),b=2