What is 2x^2+y^2-4x-4y=0 ?

The solution to 2x^2+y^2-4x-4y=0 is Ellipse with (h,k)=(1,2),a=sqrt(3),b=sqrt(6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+y^2-4x-4y=0

2 x^{2} + y^{2} - 4 x - 4 y = 0

(h, k) = (1, 2), a = 3, b = 6

Solution steps

2 x^{2} + y^{2} - 4 x - 4 y = 0

Rewrite

2 x^{2} + y^{2} - 4 x - 4 y = 0

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 2 ) ^{2}}{( 6 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 2), a = 3, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, 2), b = 6, a = 3

25 x^{2} + y^{2} + 100 x + 4 y + 79 = 0

\frac{y ^{2}}{4} + z^{2} = 1

\frac{x ^{2}}{( 1.587 ) ^{2}} + \frac{y ^{2}}{1} = 1

\frac{4}{3} x^{2} + \frac{4}{3} y^{2} = (x - 2)^{2}

9 x^{2} + 25 y^{2} + 36 x - 100 y - 89 = 0

What is 2x^2+y^2-4x-4y=0 ?
The solution to 2x^2+y^2-4x-4y=0 is Ellipse with (h,k)=(1,2),a=sqrt(3),b=sqrt(6)