What is (((x+1)^2))/((9))+(((y-2)^2))/((4))=1 ?

The solution to (((x+1)^2))/((9))+(((y-2)^2))/((4))=1 is Ellipse with (h,k)=(-1,2),a=3,b=2

Popular >

(((x+1)^2))/((9))+(((y-2)^2))/((4))=1

\frac{( ( x + 1 ) ^{2} )}{( 9 )} + \frac{( ( y - 2 ) ^{2} )}{( 4 )} = 1

(h, k) = (- 1, 2), a = 3, b = 2

Solution steps

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{3 ^{2}} + \frac{( y - 2 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 2), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 2), a = 3, b = 2

25 xx + 9 yy - 18 y - 216 = 0

2 x^{2} + 5 y^{2} = 14

5 x^{2} + y^{2} + x + 8 y + 5 = 0

\frac{( x - 5 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{36} = 1

\frac{( x - 0 ) ^{2}}{36} + \frac{( y - 0 ) ^{2}}{20} = 1

What is (((x+1)^2))/((9))+(((y-2)^2))/((4))=1 ?
The solution to (((x+1)^2))/((9))+(((y-2)^2))/((4))=1 is Ellipse with (h,k)=(-1,2),a=3,b=2