What is 2-1=x^2+3y^2 ?

The solution to 2-1=x^2+3y^2 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(1/3)

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2-1=x^2+3y^2

2 - 1 = x^{2} + 3 y^{2}

(h, k) = (0, 0), a = 1, b = \frac{1}{3}

Solution steps

2 - 1 = x^{2} + 3 y^{2}

Rewrite

2 - 1 - x^{2} - 3 y^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{1}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = \frac{1}{3}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 1, b = \frac{1}{3}

- 25 x^{2} - 4 y^{2} = - 100

\frac{( x + 4 ) ^{2}}{49} + \frac{( y - 4 ) ^{2}}{25} = 1

y^{2} + \frac{x ^{2}}{4} = 1

f, f = 3 - x f (x)^{- 1} (x)

\frac{( x + 3 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{25} - 1 = 0

What is 2-1=x^2+3y^2 ?
The solution to 2-1=x^2+3y^2 is Ellipse with (h,k)=(0,0),a=1,b=sqrt(1/3)