What is (x^2)/3+(y^2)/4 =1 ?

The solution to (x^2)/3+(y^2)/4 =1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=2

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(x^2)/3+(y^2)/4 =1

\frac{x ^{2}}{3} + \frac{y ^{2}}{4} = 1

(h, k) = (0, 0), a = 3, b = 2

Solution steps

\frac{x ^{2}}{3} + \frac{y ^{2}}{4} = 1

Rewrite

\frac{x ^{2}}{3} + \frac{y ^{2}}{4} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 3 ) ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 3

\frac{( X - 5 ) ^{2}}{25} + \frac{( y + 7 ) ^{2}}{16} = 1

6 x^{2} + 10 x + y^{2} = 0

27 x^{2} - 54 x + 48 y^{2} - 192 y - 213 = 0

\frac{( x - 5 ) ^{2}}{4} + \frac{( y - 4 ) ^{2}}{16} = 1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

What is (x^2)/3+(y^2)/4 =1 ?
The solution to (x^2)/3+(y^2)/4 =1 is Ellipse with (h,k)=(0,0),a=sqrt(3),b=2