What is (x^2)/(24)+(y^2)/(49)=1 ?

The solution to (x^2)/(24)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=2sqrt(6),b=7

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(x^2)/(24)+(y^2)/(49)=1

\frac{x ^{2}}{24} + \frac{y ^{2}}{49} = 1

(h, k) = (0, 0), a = 26, b = 7

Solution steps

\frac{x ^{2}}{24} + \frac{y ^{2}}{49} = 1

Rewrite

\frac{x ^{2}}{24} + \frac{y ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 6 ) ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 26, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 26

\frac{x ^{2}}{64} + \frac{y ^{2}}{121} = 1

\frac{( ( x + 2 ) ^{2} )}{9} + \frac{( ( y - 4 ) ^{2} )}{16} = 1

\frac{( x + 1 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{9} = 1

- 16 y + 52 = - 2 x^{2} - 8 x - y^{2}

10 x^{2} + 4 y^{2} = 14

What is (x^2)/(24)+(y^2)/(49)=1 ?
The solution to (x^2)/(24)+(y^2)/(49)=1 is Ellipse with (h,k)=(0,0),a=2sqrt(6),b=7