What is ((x+2)^2)/9+((y-7)^2)/(64)=1 ?

The solution to ((x+2)^2)/9+((y-7)^2)/(64)=1 is Ellipse with (h,k)=(-2,7),a=3,b=8

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((x+2)^2)/9+((y-7)^2)/(64)=1

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 7 ) ^{2}}{64} = 1

(h, k) = (- 2, 7), a = 3, b = 8

Solution steps

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 7 ) ^{2}}{64} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{9} + \frac{( y - 7 ) ^{2}}{64} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{3 ^{2}} + \frac{( y - 7 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 7), a = 3, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 7), b = 8, a = 3

4 x^{2} + 3 y^{2} - 12 y = 0

9 x^{2} + 4 y^{2} - 36 x = 0

- 4 x^{2} - y^{2} + 16 \geq 0

y^{2} = - 4 x^{2} + 16

\frac{( x + 5 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{4} = 1

What is ((x+2)^2)/9+((y-7)^2)/(64)=1 ?
The solution to ((x+2)^2)/9+((y-7)^2)/(64)=1 is Ellipse with (h,k)=(-2,7),a=3,b=8