What is 16x^2-96x+9y^2=0 ?

The solution to 16x^2-96x+9y^2=0 is Ellipse with (h,k)=(3,0),a=3,b=4

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16x^2-96x+9y^2=0

16 x^{2} - 96 x + 9 y^{2} = 0

(h, k) = (3, 0), a = 3, b = 4

Solution steps

16 x^{2} - 96 x + 9 y^{2} = 0

Rewrite

16 x^{2} - 96 x + 9 y^{2} = 0

in the form of the standard ellipse equation

\frac{( x - 3 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (3, 0), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (3, 0), b = 4, a = 3

20 (x + 1)^{2} + 9 y^{2} = 180

x^{2} + 5 y^{2} = \frac{1}{5}

3 x^{2} + 12 y^{2} + 18 x - 24 y - 69 = 0

x^{2} + y^{2} = - 8 y

3 y^{2} + 5 x^{2} = 20

What is 16x^2-96x+9y^2=0 ?
The solution to 16x^2-96x+9y^2=0 is Ellipse with (h,k)=(3,0),a=3,b=4