What is 2x^2+4y^2=8 ?

The solution to 2x^2+4y^2=8 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)

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2x^2+4y^2=8

2 x^{2} + 4 y^{2} = 8

(h, k) = (0, 0), a = 2, b = 2

Solution steps

2 x^{2} + 4 y^{2} = 8

Rewrite

2 x^{2} + 4 y^{2} = 8

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{2 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 2, b = 2

9 z^{2} + y^{2} = 36

\frac{( x - 3 ) ^{2}}{12} + \frac{y ^{2}}{16} = 1

4 a^{2} + 9 b^{2} = 25

3 x^{2} + 3 y^{2} + 48 y = 0

25 x^{(2)} + 4 y^{(2)} = 99

What is 2x^2+4y^2=8 ?
The solution to 2x^2+4y^2=8 is Ellipse with (h,k)=(0,0),a=2,b=sqrt(2)