What is ((x+2)^2)/4+((y-2)^2)/(36)=1 ?

The solution to ((x+2)^2)/4+((y-2)^2)/(36)=1 is Ellipse with (h,k)=(-2,2),a=2,b=6

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((x+2)^2)/4+((y-2)^2)/(36)=1

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{36} = 1

(h, k) = (- 2, 2), a = 2, b = 6

Solution steps

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{2 ^{2}} + \frac{( y - 2 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 2), a = 2, b = 6

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 2, 2), b = 6, a = 2

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 11

9 x^{2} + 25 y^{2} + 18 x + 50 y - 191 = 0

\frac{( x - 2 ) ^{2}}{5} + \frac{( y + 1 ) ^{2}}{4} = 1

6 x^{2} + y^{2} + 12 x = 0

2 - \frac{2 - 2 x}{2 x - x ^{2} - y ^{2}} = 0

What is ((x+2)^2)/4+((y-2)^2)/(36)=1 ?
The solution to ((x+2)^2)/4+((y-2)^2)/(36)=1 is Ellipse with (h,k)=(-2,2),a=2,b=6