What is ((x-4)^2)/(35)+((y-2)^2)/(39)=1 ?

The solution to ((x-4)^2)/(35)+((y-2)^2)/(39)=1 is Ellipse with (h,k)=(4,2),a=sqrt(35),b=sqrt(39)

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((x-4)^2)/(35)+((y-2)^2)/(39)=1

\frac{( x - 4 ) ^{2}}{35} + \frac{( y - 2 ) ^{2}}{39} = 1

(h, k) = (4, 2), a = 35, b = 39

Solution steps

\frac{( x - 4 ) ^{2}}{35} + \frac{( y - 2 ) ^{2}}{39} = 1

Rewrite

\frac{( x - 4 ) ^{2}}{35} + \frac{( y - 2 ) ^{2}}{39} = 1

in the form of the standard ellipse equation

\frac{( x - 4 ) ^{2}}{( 35 ) ^{2}} + \frac{( y - 2 ) ^{2}}{( 39 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (4, 2), a = 35, b = 39

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (4, 2), b = 39, a = 35

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What is ((x-4)^2)/(35)+((y-2)^2)/(39)=1 ?
The solution to ((x-4)^2)/(35)+((y-2)^2)/(39)=1 is Ellipse with (h,k)=(4,2),a=sqrt(35),b=sqrt(39)