What is (x^2)/9+((y-3)^2)/(25)=1 ?

The solution to (x^2)/9+((y-3)^2)/(25)=1 is Ellipse with (h,k)=(0,3),a=3,b=5

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(x^2)/9+((y-3)^2)/(25)=1

\frac{x ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

(h, k) = (0, 3), a = 3, b = 5

Solution steps

\frac{x ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{( y - 3 ) ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 3 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 3), a = 3, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 3), b = 5, a = 3

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9 x^{2} + 16 y^{2} - 90 x + 256 y + 1105 = 0

9 x^{2} + 25 y^{2} - 18 x - 110 y - 116 = 0

33 x^{2} + 13 y^{2} - 396 x + 267 y + 850 = 0

x^{2} + 4 x + 7 y^{2} + y = 0

What is (x^2)/9+((y-3)^2)/(25)=1 ?
The solution to (x^2)/9+((y-3)^2)/(25)=1 is Ellipse with (h,k)=(0,3),a=3,b=5