What is ((x-0)^2)/(1^2)+((y-0)^2)/(3^2)=1 ?

The solution to ((x-0)^2)/(1^2)+((y-0)^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=1,b=3

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((x-0)^2)/(1^2)+((y-0)^2)/(3^2)=1

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

(h, k) = (0, 0), a = 1, b = 3

Solution steps

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 1

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\frac{( x + 1 ) ^{2} + ( y - 1 ) ^{2}}{( x - 2 ) ^{2} + ( y + 1 ) ^{2}} = 9

\frac{x ^{2}}{9} + \frac{( y - 3 ) ^{2}}{4} = 1

x^{2} + 4 y^{2} - 6 x + 16 y = 0

2 x^{2} + 4 y^{2} + 10 x + 10 y - 3 = 0

What is ((x-0)^2)/(1^2)+((y-0)^2)/(3^2)=1 ?
The solution to ((x-0)^2)/(1^2)+((y-0)^2)/(3^2)=1 is Ellipse with (h,k)=(0,0),a=1,b=3