What is x^2+(y/4)^2=1 ?

The solution to x^2+(y/4)^2=1 is Ellipse with (h,k)=(0,0),a=1,b=4

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x^2+(y/4)^2=1

x^{2} + (\frac{y}{4})^{2} = 1

(h, k) = (0, 0), a = 1, b = 4

Solution steps

x^{2} + (\frac{y}{4})^{2} = 1

Rewrite

x^{2} + (\frac{y}{4})^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 1

\frac{( x - 2 ) ^{2}}{4} + \frac{( y - 1 ) ^{2}}{3} = 1

2 x^{2} + y^{2} = 16

4 (x - 4)^{2} + 9 (y - 2)^{2} = 36

\frac{( y + 7 ) ^{2}}{16} + \frac{( x - 5 ) ^{2}}{25} = 1

\frac{4}{x + y i} = x - y i

What is x^2+(y/4)^2=1 ?
The solution to x^2+(y/4)^2=1 is Ellipse with (h,k)=(0,0),a=1,b=4