What is ((x+2)^2)/(64)+((y-8)^2)/(36)=1 ?

The solution to ((x+2)^2)/(64)+((y-8)^2)/(36)=1 is Ellipse with (h,k)=(-2,8),a=8,b=6

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((x+2)^2)/(64)+((y-8)^2)/(36)=1

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 8 ) ^{2}}{36} = 1

(h, k) = (- 2, 8), a = 8, b = 6

Solution steps

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 8 ) ^{2}}{36} = 1

Rewrite

\frac{( x + 2 ) ^{2}}{64} + \frac{( y - 8 ) ^{2}}{36} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 2 ) ) ^{2}}{8 ^{2}} + \frac{( y - 8 ) ^{2}}{6 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 2, 8), a = 8, b = 6

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 2, 8), a = 8, b = 6

16 x^{2} + 25 y^{2} = \frac{169}{4}

\frac{( x - 3 ) ^{2}}{16} + (\frac{( y + 4 )}{9})^{2} = 1

9 x^{2} + 5 y^{2} = 180

\frac{( x - 2 ) ^{2}}{36} + \frac{( y + 5 ) ^{2}}{29} = 1

\frac{( x - 4 ) ^{2}}{36} + \frac{( y + 1 ) ^{2}}{10} = 1

What is ((x+2)^2)/(64)+((y-8)^2)/(36)=1 ?
The solution to ((x+2)^2)/(64)+((y-8)^2)/(36)=1 is Ellipse with (h,k)=(-2,8),a=8,b=6