What is ((3x^2)/4)/(12)+(((4y)/4)/(12))^2=1 ?

The solution to ((3x^2)/4)/(12)+(((4y)/4)/(12))^2=1 is Ellipse with (h,k)=(0,0),a=4,b=12

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((3x^2)/4)/(12)+(((4y)/4)/(12))^2=1

\frac{\frac{3 x ^{2}}{4}}{12} + (\frac{\frac{4 y}{4}}{12})^{2} = 1

(h, k) = (0, 0), a = 4, b = 12

Solution steps

\frac{\frac{3 x ^{2}}{4}}{12} + (\frac{\frac{4 y}{4}}{12})^{2} = 1

Rewrite

\frac{\frac{3 x ^{2}}{4}}{12} + (\frac{\frac{4 y}{4}}{12})^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{1 2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 12

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 12, a = 4

\frac{( X + 7 ) ^{2}}{16} + \frac{( Y - 5 ) ^{2}}{25} = 1

\frac{y}{( \frac{x}{5} ) ^{2} + ( \frac{y}{2} ) ^{2}} = 1

(\frac{X - 2}{2})^{2} + (\frac{Y + 3}{4})^{2} = 1

225 x^{2} + 289 y^{2} = 65025

(2 x^{2} + y^{2})^{2} = (3 - y)^{2}

What is ((3x^2)/4)/(12)+(((4y)/4)/(12))^2=1 ?
The solution to ((3x^2)/4)/(12)+(((4y)/4)/(12))^2=1 is Ellipse with (h,k)=(0,0),a=4,b=12