What is ((x+1)^2}{49}+\frac{(y-7)^2)/1 =1 ?

The solution to ((x+1)^2}{49}+\frac{(y-7)^2)/1 =1 is Ellipse with (h,k)=(-1,7),a=7,b=1

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((x+1)^2}{49}+\frac{(y-7)^2)/1 =1

\frac{( x + 1 ) ^{2}}{49} + \frac{( y - 7 ) ^{2}}{1} = 1

(h, k) = (- 1, 7), a = 7, b = 1

Solution steps

\frac{( x + 1 ) ^{2}}{49} + \frac{( y - 7 ) ^{2}}{1} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{49} + \frac{( y - 7 ) ^{2}}{1} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{7 ^{2}} + \frac{( y - 7 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 7), a = 7, b = 1

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 7), a = 7, b = 1

4 (x - 3)^{2} + 2 (y + 4)^{2} = 16

3 x^{2} - 12 x + y^{2} - 4 y + 1 = 0

(\frac{u + v}{u ^{2} + v ^{2}}) + (\frac{- v + u}{u ^{2} + v ^{2}}) = 1

3 x^{2} + 2 y^{2} - 6 = 0

\frac{y ^{2}}{64} + \frac{x ^{2}}{100} = 1

What is ((x+1)^2}{49}+\frac{(y-7)^2)/1 =1 ?
The solution to ((x+1)^2}{49}+\frac{(y-7)^2)/1 =1 is Ellipse with (h,k)=(-1,7),a=7,b=1