What is (((x+0)^2))/(100)+(((y+0)^2))/(49)=1 ?

The solution to (((x+0)^2))/(100)+(((y+0)^2))/(49)=1 is Ellipse with (h,k)=(0,0),a=10,b=7

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(((x+0)^2))/(100)+(((y+0)^2))/(49)=1

\frac{( ( x + 0 ) ^{2} )}{100} + \frac{( ( y + 0 ) ^{2} )}{49} = 1

(h, k) = (0, 0), a = 10, b = 7

Solution steps

\frac{( x + 0 ) ^{2}}{100} + \frac{( y + 0 ) ^{2}}{49} = 1

Rewrite

\frac{( x + 0 ) ^{2}}{100} + \frac{( y + 0 ) ^{2}}{49} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{7 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 7

2 x^{2} + 3 y^{2} + 9 x + 10 y - 3 = 0

\frac{( x - 9 ) ^{2}}{64} + \frac{( y + 2 ) ^{2}}{25} = 1

\frac{( x - 2 ) ^{2}}{3. 5 ^{2}} + \frac{( y - 1 ) ^{2}}{2. 5 ^{2}} = 1

(3 p + 2 q) 2 = 9 p^{2} + 4 q^{2}

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{36} = 1

What is (((x+0)^2))/(100)+(((y+0)^2))/(49)=1 ?
The solution to (((x+0)^2))/(100)+(((y+0)^2))/(49)=1 is Ellipse with (h,k)=(0,0),a=10,b=7