What is (x^2)/(100)+(y^2)/(52)=1 ?

The solution to (x^2)/(100)+(y^2)/(52)=1 is Ellipse with (h,k)=(0,0),a=10,b=2sqrt(13)

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(x^2)/(100)+(y^2)/(52)=1

\frac{x ^{2}}{100} + \frac{y ^{2}}{52} = 1

(h, k) = (0, 0), a = 10, b = 213

Solution steps

\frac{x ^{2}}{100} + \frac{y ^{2}}{52} = 1

Rewrite

\frac{x ^{2}}{100} + \frac{y ^{2}}{52} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 0 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 13 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 213

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = 213

\frac{( x - 14 ) ^{2}}{3} + \frac{( y - 11 ) ^{2}}{4} = 1

x^{2} + 7 y^{2} = 12

\frac{( x - 3 ) ^{2}}{64} + \frac{( y + 1 ) ^{2}}{25} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} < 1

\frac{( x + 4 ) ^{2}}{4} + \frac{( y - 2 ) ^{2}}{3} = 1

What is (x^2)/(100)+(y^2)/(52)=1 ?
The solution to (x^2)/(100)+(y^2)/(52)=1 is Ellipse with (h,k)=(0,0),a=10,b=2sqrt(13)