What is (x^2)/9+(y^2)/(9/25)=1 ?

The solution to (x^2)/9+(y^2)/(9/25)=1 is Ellipse with (h,k)=(0,0),a=3,b= 3/5

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(x^2)/9+(y^2)/(9/25)=1

\frac{x ^{2}}{9} + \frac{y ^{2}}{\frac{9}{25}} = 1

(h, k) = (0, 0), a = 3, b = \frac{3}{5}

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{\frac{9}{25}} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{\frac{9}{25}} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{3}{5} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = \frac{3}{5}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = \frac{3}{5}

y = 4 - \frac{x ^{2}}{4 y}

3 x^{2} + y^{2} - 12 = 0

4 y^{2} + x^{2} - 2 x = 3

\frac{( x ) ^{2}}{49} + \frac{( y ) ^{2}}{25} = 1

\frac{( - y )}{- 2 - x} = \frac{( - 1 )}{\frac{( 4 - y )}{6 - x}}

What is (x^2)/9+(y^2)/(9/25)=1 ?
The solution to (x^2)/9+(y^2)/(9/25)=1 is Ellipse with (h,k)=(0,0),a=3,b= 3/5