What is 4x^2+3y^2=7 ?

The solution to 4x^2+3y^2=7 is Ellipse with (h,k)=(0,0),a=(sqrt(7))/2 ,b=sqrt(7/3)

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4x^2+3y^2=7

4 x^{2} + 3 y^{2} = 7

(h, k) = (0, 0), a = \frac{7}{2}, b = \frac{7}{3}

Solution steps

4 x^{2} + 3 y^{2} = 7

Rewrite

4 x^{2} + 3 y^{2} = 7

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{7}{2} ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{7}{3} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{7}{2}, b = \frac{7}{3}

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = \frac{7}{3}, a = \frac{7}{2}

25 x^{2} + 4 y^{2} - 250 x - 16 y = - 541

x^{2} + \frac{z ^{2}}{225} = 1

4 x^{2} + 12 y^{2} - 4 x - 24 y + 1 = 0

\frac{x ^{2}}{4} + x + 9 y^{2} + 18 y + \frac{31}{4} = 0

15 x^{2} + 9 y^{2} = 225

What is 4x^2+3y^2=7 ?
The solution to 4x^2+3y^2=7 is Ellipse with (h,k)=(0,0),a=(sqrt(7))/2 ,b=sqrt(7/3)