What is ((x^2)/(16))+((y^2)/(25))=1 ?

The solution to ((x^2)/(16))+((y^2)/(25))=1 is Ellipse with (h,k)=(0,0),a=4,b=5

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((x^2)/(16))+((y^2)/(25))=1

(\frac{x ^{2}}{16}) + (\frac{y ^{2}}{25}) = 1

(h, k) = (0, 0), a = 4, b = 5

Solution steps

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 4

\frac{( x + 4 ) ^{2}}{6 ^{2}} + \frac{( y + 6 ) ^{2}}{7 ^{2}} = 1

X^{2} + 4 Y^{2} - 6 X - 16 Y + 21 = 0

(5 p + 3 q) 2 = 25 p^{2} + 9 q^{2}

25 x^{2} + 9 y^{2} + 100 x + 36 y - 89 = 0

\frac{x ^{2}}{4} + (1 - \frac{y}{2})^{2} = 1

What is ((x^2)/(16))+((y^2)/(25))=1 ?
The solution to ((x^2)/(16))+((y^2)/(25))=1 is Ellipse with (h,k)=(0,0),a=4,b=5