What is 64xx-256x+81yy+810y=2903 ?

The solution to 64xx-256x+81yy+810y=2903 is Ellipse with (h,k)=(2,-5),a=9,b=8

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64xx-256x+81yy+810y=2903

64 xx - 256 x + 81 yy + 810 y = 2903

(h, k) = (2, - 5), a = 9, b = 8

Solution steps

64 xx - 256 x + 81 yy + 810 y = 2903

Rewrite

64 xx - 256 x + 81 yy + 810 y = 2903

in the form of the standard ellipse equation

\frac{( x - 2 ) ^{2}}{9 ^{2}} + \frac{( y - ( - 5 ) ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (2, - 5), a = 9, b = 8

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (2, - 5), a = 9, b = 8

\frac{( x + 4 ) ^{2}}{9} + \frac{( y - 4 ) ^{2}}{16} = 1

(\frac{x - 1}{36})^{2} + (\frac{y + 2}{25})^{2} = 1

9 x^{2} + 36 y^{2} + 36 x - 216 y + 36 = 0

\frac{( x - 4 ) ^{2}}{25} + \frac{( y - 2 ) ^{2}}{1} = 1

25 x^{2} + 16 y^{2} - 400 = 0

What is 64xx-256x+81yy+810y=2903 ?
The solution to 64xx-256x+81yy+810y=2903 is Ellipse with (h,k)=(2,-5),a=9,b=8