What is (25x^2+16y^2)/(400)=1 ?

The solution to (25x^2+16y^2)/(400)=1 is Ellipse with (h,k)=(0,0),a=4,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(25x^2+16y^2)/(400)=1

\frac{25 x ^{2} + 16 y ^{2}}{400} = 1

(h, k) = (0, 0), a = 4, b = 5

Solution steps

\frac{25 x ^{2} + 16 y ^{2}}{400} = 1

Rewrite

\frac{25 x ^{2} + 16 y ^{2}}{400} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 4

\frac{y ^{2}}{16} + \frac{x ^{2}}{4} = 1

12 x^{2} + 8 y^{2} = 96

10 x^{2} + 3 y^{2} = 30

\frac{x ^{2}}{k} + \frac{y ^{2}}{4 + k} = 1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 5 ) ^{2}}{9} = 1

What is (25x^2+16y^2)/(400)=1 ?
The solution to (25x^2+16y^2)/(400)=1 is Ellipse with (h,k)=(0,0),a=4,b=5