What is -16-x^2-y^2>= 0 ?

The solution to -16-x^2-y^2>= 0 is Ellipse with (h,k)=(0,0),a=4,b=4

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-16-x^2-y^2>= 0

- 16 - x^{2} - y^{2} \geq 0

(h, k) = (0, 0), a = 4, b = 4

Solution steps

- 16 - x^{2} - y^{2} \geq 0

Rewrite

- 16 - x^{2} - y^{2} \geq 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 4, a = 4

9 = 4 x^{2} + y^{2}

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 1 ) ^{2}}{36} = 1

\frac{- 6}{4} = \frac{x ^{2}}{1} + \frac{y ^{2}}{1}

\frac{( x - 3 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{25} = 1

9 x^{2} + 25 y^{2} - 54 x + 100 y - 44 = 0

What is -16-x^2-y^2>= 0 ?
The solution to -16-x^2-y^2>= 0 is Ellipse with (h,k)=(0,0),a=4,b=4