What is ((x+1)^2)/(64)+((y-6)^2)/(16)=1 ?

The solution to ((x+1)^2)/(64)+((y-6)^2)/(16)=1 is Ellipse with (h,k)=(-1,6),a=8,b=4

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((x+1)^2)/(64)+((y-6)^2)/(16)=1

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{16} = 1

(h, k) = (- 1, 6), a = 8, b = 4

Solution steps

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{16} = 1

Rewrite

\frac{( x + 1 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 1 ) ) ^{2}}{8 ^{2}} + \frac{( y - 6 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 1, 6), a = 8, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 1, 6), a = 8, b = 4

\frac{( x + 3 ) ^{2}}{25} + \frac{( y + 1 ) ^{2}}{9} = 1

4 x^{2} - 48 x + 9 y^{2} + 72 y + 144 = 0

\frac{( x - 2.22 ) ^{2}}{2.54} + \frac{y ^{2}}{1.11} = 2

25 x^{2} + 16 y^{2} - 100 x - 64 y - 236 = 0

12 x - 5 y + 10 x^{2} + 25 = \frac{- ( 100 y ^{2} )}{10 + 3}

What is ((x+1)^2)/(64)+((y-6)^2)/(16)=1 ?
The solution to ((x+1)^2)/(64)+((y-6)^2)/(16)=1 is Ellipse with (h,k)=(-1,6),a=8,b=4