What is 3x^2+2y^2-18=0 ?

The solution to 3x^2+2y^2-18=0 is Ellipse with (h,k)=(0,0),a=sqrt(6),b=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3x^2+2y^2-18=0

3 x^{2} + 2 y^{2} - 18 = 0

(h, k) = (0, 0), a = 6, b = 3

Solution steps

3 x^{2} + 2 y^{2} - 18 = 0

Rewrite

3 x^{2} + 2 y^{2} - 18 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 6 ) ^{2}} + \frac{( y - 0 ) ^{2}}{3 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 3, a = 6

3 x^{2} + 4 y^{2} = \frac{1}{2}

5 x^{2} + 9 y^{2} - 10 x + 4 = 0

3 x^{(2)} + y^{(2)} - 24 x + 39 = 0

(x - 1)^{2} + \frac{( y - 3 ) ^{2}}{2} = 1

(x - 2)^{2} + (y + 1)^{2} = 5 - 5 y^{2}

What is 3x^2+2y^2-18=0 ?
The solution to 3x^2+2y^2-18=0 is Ellipse with (h,k)=(0,0),a=sqrt(6),b=3