What is (x-0.017)^2+((y^2)/((0.999)^2))=1 ?

The solution to (x-0.017)^2+((y^2)/((0.999)^2))=1 is Ellipse with (h,k)=(0.017,0),a=1,b=0.999

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(x-0.017)^2+((y^2)/((0.999)^2))=1

(x - 0.017)^{2} + (\frac{y ^{2}}{( 0.999 ) ^{2}}) = 1

(h, k) = (0.017, 0), a = 1, b = 0.999

Solution steps

(x - 0.017)^{2} + \frac{y ^{2}}{0.99 9 ^{2}} = 1

Rewrite

(x - 0.017)^{2} + \frac{y ^{2}}{0.99 9 ^{2}} = 1

in the form of the standard ellipse equation

\frac{( x - 0.017 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{0.99 9 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0.017, 0), a = 1, b = 0.999

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0.017, 0), a = 1, b = 0.999

x^{2} - x y + \frac{1}{2} (x + y)^{2} = 4

(4 x^{2} - 8 x) + (9 y^{2} - 36 y) = - 4

2 = x^{2} + 4 y^{2}

\frac{x ^{2}}{1 ^{2}} + \frac{y ^{2}}{0.4375 ^{2}} = 1

22 x^{2} + 66 y^{2} + 60 x + 4 y - 9 = 0

What is (x-0.017)^2+((y^2)/((0.999)^2))=1 ?
The solution to (x-0.017)^2+((y^2)/((0.999)^2))=1 is Ellipse with (h,k)=(0.017,0),a=1,b=0.999