What is x^2+4y^2-12x-16y=48 ?

The solution to x^2+4y^2-12x-16y=48 is Ellipse with (h,k)=(6,2),a=10,b=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+4y^2-12x-16y=48

x^{2} + 4 y^{2} - 12 x - 16 y = 48

(h, k) = (6, 2), a = 10, b = 5

Solution steps

x^{2} + 4 y^{2} - 12 x - 16 y = 48

Rewrite

x^{2} + 4 y^{2} - 12 x - 16 y = 48

in the form of the standard ellipse equation

\frac{( x - 6 ) ^{2}}{1 0 ^{2}} + \frac{( y - 2 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (6, 2), a = 10, b = 5

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (6, 2), a = 10, b = 5

2 x^{2} + y^{2} \leq 2

(x - 3)^{2} + (\frac{y + 3}{16})^{2} = 1

(\frac{1}{4}) x^{2} + y^{2} = \frac{1}{4}

100 x^{2} + 4 y^{2} + 1200 x - 32 y + 3264 = 0

16 x^{2} + 15 y^{2} - 64 x - 90 y - 41 = 0

What is x^2+4y^2-12x-16y=48 ?
The solution to x^2+4y^2-12x-16y=48 is Ellipse with (h,k)=(6,2),a=10,b=5