What is 7x^2+2y^2=14 ?

The solution to 7x^2+2y^2=14 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(7)

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7x^2+2y^2=14

7 x^{2} + 2 y^{2} = 14

(h, k) = (0, 0), a = 2, b = 7

Solution steps

7 x^{2} + 2 y^{2} = 14

Rewrite

7 x^{2} + 2 y^{2} = 14

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 2, b = 7

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 7, a = 2

4 x^{2} + 25 y^{2} - 6 x + 200 y + 304 = 0

(\frac{x + 4}{3})^{2} + (\frac{y + 4}{9})^{2} = (\frac{457}{81})^{2}

\frac{( x - 1 ) ^{2}}{16} + \frac{( y - 2 ) ^{2}}{36} = 1

16 x^{2} + y^{2} + 64 x + 4 y + 52 = 0

7 x^{2} + 4 y^{2} + 24 y = - 8

What is 7x^2+2y^2=14 ?
The solution to 7x^2+2y^2=14 is Ellipse with (h,k)=(0,0),a=sqrt(2),b=sqrt(7)