What is 16x^2+y^2=1 ?

The solution to 16x^2+y^2=1 is Ellipse with (h,k)=(0,0),a= 1/4 ,b=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

16x^2+y^2=1

16 x^{2} + y^{2} = 1

(h, k) = (0, 0), a = \frac{1}{4}, b = 1

Solution steps

16 x^{2} + y^{2} = 1

Rewrite

16 x^{2} + y^{2} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( \frac{1}{4} ) ^{2}} + \frac{( y - 0 ) ^{2}}{1 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = \frac{1}{4}, b = 1

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 1, a = \frac{1}{4}

16 x^{2} + 4 y^{2} - 128 x - 16 y + 206 = 0

2 x^{2} + 6 y^{2} = 168

x^{2} + 25 y^{2} = 1

\frac{( x - 4 ) ^{2}}{25} + \frac{( y + 2 ) ^{2}}{64} = 1

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 2 ) ^{2}}{36} = 1

What is 16x^2+y^2=1 ?
The solution to 16x^2+y^2=1 is Ellipse with (h,k)=(0,0),a= 1/4 ,b=1