What is (X/3)^2+(Y/2)^2=1 ?

The solution to (X/3)^2+(Y/2)^2=1 is Ellipse with (h,k)=(0,0),a=3,b=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(X/3)^2+(Y/2)^2=1

(\frac{X}{3})^{2} + (\frac{Y}{2})^{2} = 1

(h, k) = (0, 0), a = 3, b = 2

Solution steps

(\frac{X}{3})^{2} + (\frac{Y}{2})^{2} = 1

Rewrite

(\frac{X}{3})^{2} + (\frac{Y}{2})^{2} = 1

in the form of the standard ellipse equation

\frac{( X - 0 ) ^{2}}{3 ^{2}} + \frac{( Y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 2

x^{2} + 14 (y - \frac{13}{14})^{2} - \frac{125}{14} = 0

\frac{( x - 3 ) ^{2}}{49} + \frac{( y + 1 ) ^{2}}{4} = 1

7 x^{2} + 3 y^{2} - 42 x + 6 y - 39 = 0

3 x^{2} + 5 y^{2} = 8

x^{2} + y^{2} = \frac{1}{2} (y + 1)^{2}

What is (X/3)^2+(Y/2)^2=1 ?
The solution to (X/3)^2+(Y/2)^2=1 is Ellipse with (h,k)=(0,0),a=3,b=2