What is ((x+9)^2)/2+(y^2)/3 =1 ?

The solution to ((x+9)^2)/2+(y^2)/3 =1 is Ellipse with (h,k)=(-9,0),a=sqrt(2),b=sqrt(3)

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((x+9)^2)/2+(y^2)/3 =1

\frac{( x + 9 ) ^{2}}{2} + \frac{y ^{2}}{3} = 1

(h, k) = (- 9, 0), a = 2, b = 3

Solution steps

\frac{( x + 9 ) ^{2}}{2} + \frac{y ^{2}}{3} = 1

Rewrite

\frac{( x + 9 ) ^{2}}{2} + \frac{y ^{2}}{3} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 9 ) ) ^{2}}{( 2 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 9, 0), a = 2, b = 3

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 9, 0), b = 3, a = 2

\frac{x ^{2}}{625} + \frac{y ^{2}}{400} = 1

14 x^{2} + 8 y^{2} = 112

9 y^{2} + z^{2} = 36

2 x^{2} + 8 y^{2} = 18

2 x^{2} + 8 y^{2} = 15

What is ((x+9)^2)/2+(y^2)/3 =1 ?
The solution to ((x+9)^2)/2+(y^2)/3 =1 is Ellipse with (h,k)=(-9,0),a=sqrt(2),b=sqrt(3)