What is (x^2)/9+(y^2)/7 =1 ?

The solution to (x^2)/9+(y^2)/7 =1 is Ellipse with (h,k)=(0,0),a=3,b=sqrt(7)

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(x^2)/9+(y^2)/7 =1

\frac{x ^{2}}{9} + \frac{y ^{2}}{7} = 1

(h, k) = (0, 0), a = 3, b = 7

Solution steps

\frac{x ^{2}}{9} + \frac{y ^{2}}{7} = 1

Rewrite

\frac{x ^{2}}{9} + \frac{y ^{2}}{7} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{( 7 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 7

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 7

\frac{y ^{2}}{a ^{2}} + \frac{x ^{2}}{b ^{2}} = 1

2 x^{2} + 8 y^{2} = 50

\frac{( y - 1 ) ^{2}}{16} + \frac{( x + 3 ) ^{2}}{4} = 1

3 x^{2} + y^{2} = 6

0.2 x^{2} + 2 y^{2} + 4 x - 8 y - 12 = 0

What is (x^2)/9+(y^2)/7 =1 ?
The solution to (x^2)/9+(y^2)/7 =1 is Ellipse with (h,k)=(0,0),a=3,b=sqrt(7)