What is ((x-1)^2)/(4^2)+((y-5)^2)/(b^2)=1 ?

The solution to ((x-1)^2)/(4^2)+((y-5)^2)/(b^2)=1 is Ellipse with (h,k)=(1,5),a=4,b=b

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((x-1)^2)/(4^2)+((y-5)^2)/(b^2)=1

\frac{( x - 1 ) ^{2}}{4 ^{2}} + \frac{( y - 5 ) ^{2}}{b ^{2}} = 1

(h, k) = (1, 5), a = 4, b = b

Solution steps

\frac{( x - 1 ) ^{2}}{4 ^{2}} + \frac{( y - 5 ) ^{2}}{b ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, 5), a = 4, b = b

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (1, 5), a = 4, b = b

x^{(2)} + 3 y^{(2)} - 6 x + 6 y = 0

5 x^{2} + 13 y^{2} - 65 = 0

y^{2} = 1 - 16 x^{2}

4 x^{2} + y^{2} + 12 x + 6 y + 5 = 0

2 y^{2} + 4 z^{2} = 4

What is ((x-1)^2)/(4^2)+((y-5)^2)/(b^2)=1 ?
The solution to ((x-1)^2)/(4^2)+((y-5)^2)/(b^2)=1 is Ellipse with (h,k)=(1,5),a=4,b=b