What is 4x^2+7y^2-140=0 ?

The solution to 4x^2+7y^2-140=0 is Ellipse with (h,k)=(0,0),a=sqrt(35),b=2sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2+7y^2-140=0

4 x^{2} + 7 y^{2} - 140 = 0

(h, k) = (0, 0), a = 35, b = 25

Solution steps

4 x^{2} + 7 y^{2} - 140 = 0

Rewrite

4 x^{2} + 7 y^{2} - 140 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 35 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 5 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 35, b = 25

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 35, b = 25

x^{2} + 5 y^{2} - 30 y + 25 = 0

3 x^{2} + 9 y^{2} - 6 x - 7 y - 8 = 0

\frac{x ^{2}}{25} + \frac{y ^{2}}{39} = 1

x^{2} = 6 y - y^{2}

\frac{( x - 81 ) ^{2}}{6 4 ^{2}} + \frac{( y - 64 ) ^{2}}{8 1 ^{2}} = 1

What is 4x^2+7y^2-140=0 ?
The solution to 4x^2+7y^2-140=0 is Ellipse with (h,k)=(0,0),a=sqrt(35),b=2sqrt(5)