What is the vertices 4x^2+9y^2-16x+18y-11=0 ?

The vertices 4x^2+9y^2-16x+18y-11=0 is (5,-1),(-1,-1)

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vertices 4x^2+9y^2-16x+18y-11=0

vertices

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0

(5, - 1), (- 1, - 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} - 16 x + 18 y - 11 = 0 :

Ellipse with center

(h, k) = (2, - 1), a = 3, b = 2

(2 + 3, - 1), (2 - 3, - 1)

Refine

(5, - 1), (- 1, - 1)

\frac{x ^{2}}{16} + \frac{y ^{2}}{12} = 1

41 x^{2} + 16 y^{2} + 246 x - 192 y + 289 = 0

4 x^{2} + y^{2} - 8 x + 4 y - 8 = 0

\frac{x ^{2}}{4} + \frac{y ^{2}}{25} = 1

x^{2} + y^{2} - 4 y = 0

What is the vertices 4x^2+9y^2-16x+18y-11=0 ?
The vertices 4x^2+9y^2-16x+18y-11=0 is (5,-1),(-1,-1)