What is the vertices (x^2)/(100)+(y^2)/(64)=1 ?

The vertices (x^2)/(100)+(y^2)/(64)=1 is (10,0),(-10,0)

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vertices (x^2)/(100)+(y^2)/(64)=1

vertices

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1

(10, 0), (- 10, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{100} + \frac{y ^{2}}{64} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 10, b = 8

(0 + 10, 0), (0 - 10, 0)

Refine

(10, 0), (- 10, 0)

\frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{5} = 1

9 x^{2} + y^{2} = 84

\frac{( x - 4 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{9} = 1

9 x^{2} + 4 y^{2} - 18 x + 16 y - 11 = 0

3 x^{2} + 7 y^{2} = 63

What is the vertices (x^2)/(100)+(y^2)/(64)=1 ?
The vertices (x^2)/(100)+(y^2)/(64)=1 is (10,0),(-10,0)