What is the vertices 4x^2+9y^2-32x-36y+64=0 ?

The vertices 4x^2+9y^2-32x-36y+64=0 is (7,2),(1,2)

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vertices 4x^2+9y^2-32x-36y+64=0

vertices

4 x^{2} + 9 y^{2} - 32 x - 36 y + 64 = 0

(7, 2), (1, 2)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

4 x^{2} + 9 y^{2} - 32 x - 36 y + 64 = 0 :

Ellipse with center

(h, k) = (4, 2), a = 3, b = 2

(4 + 3, 2), (4 - 3, 2)

Refine

(7, 2), (1, 2)

x^{2} + 16 y^{2} = 1

2 x^{2} + 7 y^{2} = 14

16 x^{2} + 25 y^{2} - 1600 = 0

\frac{x ^{2}}{16} + \frac{( y - 2 ) ^{2}}{9} = 1

x^{2} + 10 x + 9 y^{2} + 16 = 0

What is the vertices 4x^2+9y^2-32x-36y+64=0 ?
The vertices 4x^2+9y^2-32x-36y+64=0 is (7,2),(1,2)