What is the vertices (x^2)/(8^2)+(y^2)/(4^2)=1 ?

The vertices (x^2)/(8^2)+(y^2)/(4^2)=1 is (8,0),(-8,0)

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vertices (x^2)/(8^2)+(y^2)/(4^2)=1

vertices

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1

(8, 0), (- 8, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

\frac{x ^{2}}{8 ^{2}} + \frac{y ^{2}}{4 ^{2}} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 8, b = 4

(0 + 8, 0), (0 - 8, 0)

Refine

(8, 0), (- 8, 0)

4 x^{2} + 25 y^{2} - 100 = 0

16 x^{2} + 25 y^{2} - 400 = 0

\frac{x ^{2}}{9} + y^{2} = 1

\frac{x ^{2}}{4 ^{2}} + \frac{y ^{2}}{3 ^{2}} = 1

25 x^{2} + 9 y^{2} - 200 x - 36 y + 211 = 0

What is the vertices (x^2)/(8^2)+(y^2)/(4^2)=1 ?
The vertices (x^2)/(8^2)+(y^2)/(4^2)=1 is (8,0),(-8,0)