What is the vertices x^2-4x+100y^2+200y+4=0 ?

The vertices x^2-4x+100y^2+200y+4=0 is (12,-1),(-8,-1)

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vertices x^2-4x+100y^2+200y+4=0

vertices

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0

(12, - 1), (- 8, - 1)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} - 4 x + 100 y^{2} + 200 y + 4 = 0 :

Ellipse with center

(h, k) = (2, - 1), a = 10, b = 1

(2 + 10, - 1), (2 - 10, - 1)

Refine

(12, - 1), (- 8, - 1)

9 x^{2} - 54 x + y^{2} + 2 y + 46 = 0

12 (x + 4)^{2} + 3 (y - 1)^{2} = 48

4 x^{2} + 25 y^{2} = 100

9 x^{2} + 18 x + 4 y^{2} - 24 y + 9 = 0

3 x^{2} + 12 y^{2} - 6 x - 48 y + 33 = 0

What is the vertices x^2-4x+100y^2+200y+4=0 ?
The vertices x^2-4x+100y^2+200y+4=0 is (12,-1),(-8,-1)