What is the vertices x^2+2y^2+2x-20y+43=0 ?

The vertices x^2+2y^2+2x-20y+43=0 is (-1+2sqrt(2),5),(-1-2sqrt(2),5)

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vertices x^2+2y^2+2x-20y+43=0

vertices

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0

(- 1 + 22, 5), (- 1 - 22, 5)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

x^{2} + 2 y^{2} + 2 x - 20 y + 43 = 0 :

Ellipse with center

(h, k) = (- 1, 5), a = 22, b = 2

(- 1 + 22, 5), (- 1 - 22, 5)

x^{2} + y^{2} + 8 x = 32

4 x^{2} + 9 y^{2} - 16 x + 36 y + 16 = 0

25 x^{2} + 81 y^{2} = 2025

18 x^{2} + 4 y^{2} - 72 x + 4 y + 37 = 0

4 - 9 x^{2} - 2 y^{2} = 0

What is the vertices x^2+2y^2+2x-20y+43=0 ?
The vertices x^2+2y^2+2x-20y+43=0 is (-1+2sqrt(2),5),(-1-2sqrt(2),5)