What is the vertices 25x^2+144y^2=900 ?

The vertices 25x^2+144y^2=900 is (6,0),(-6,0)

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vertices 25x^2+144y^2=900

vertices

25 x^{2} + 144 y^{2} = 900

(6, 0), (- 6, 0)

Solution steps

(h + a, k), (h - a, k)

Calculate ellipse properties

25 x^{2} + 144 y^{2} = 900 :

Ellipse with center

(h, k) = (0, 0), a = 6, b = \frac{5}{2}

(0 + 6, 0), (0 - 6, 0)

Refine

(6, 0), (- 6, 0)

4 x^{2} + 16 y^{2} - 16 x - 48 = 0

25 (x + 2)^{2} + 4 (y - 3)^{2} = 100

4 x^{2} + y^{2} + 6 y + 5 = 0

\frac{( x + 2 ) ^{2}}{16} + \frac{y ^{2}}{49} = 1

(\frac{x}{7})^{2} + (\frac{y}{5})^{2} = 1

What is the vertices 25x^2+144y^2=900 ?
The vertices 25x^2+144y^2=900 is (6,0),(-6,0)