What is the vertices 27x^2+y^2-18y=0 ?

The vertices 27x^2+y^2-18y=0 is (0,18),(0,0)

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vertices 27x^2+y^2-18y=0

vertices

27 x^{2} + y^{2} - 18 y = 0

(0, 18), (0, 0)

Solution steps

(h, k + b), (h, k - b)

Calculate ellipse properties

27 x^{2} + y^{2} - 18 y = 0 :

Ellipse with center

(h, k) = (0, 9), b = 9, a = 3

(0, 9 + 9), (0, 9 - 9)

Refine

(0, 18), (0, 0)

\frac{( x - 2 ) ^{2}}{5} + \frac{( y + 3 ) ^{2}}{9} = 1

25 x^{2} + y^{2} - 4 y - 21 = 0

9 x^{2} - 72 x + y^{2} + 4 y + 112 = 0

4 x^{2} + 9 y^{2} = 1

4 x^{2} + y^{2} = 4

What is the vertices 27x^2+y^2-18y=0 ?
The vertices 27x^2+y^2-18y=0 is (0,18),(0,0)